手写代码：斐波那契数列

参考回答：



long long Fib(long long N){long long first = 1;long long second = 1;long long ret = 0;for (int i = 3; i <=N; ++i){ret = first + second;first = second;second = ret;}return second;}

	
	

	

		

			

				

					Was this helpful?
				
			
			
							
				

					YesNo
				
				
			
		
		

			

				

					0 / 
					0
				
				
				
			
		
		
		

	
			

			

				

			上一篇: 手写代码：二分查找的代码？		
				
				

					下一篇: 请问你知道什么加密算法吗