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<pre><code>请编写一个函数实现将IP地址转换成一个整数。
如 10.3.9.12 转换规则为:
10 00001010
3 00000011
9 00001001
12 00001100
再将以上二进制拼接起来计算十进制结果:00001010 00000011 00001001 00001100 = ?
def v1(addr):
# 取每个数
id = [int(x) for x in addr.split(""."")]
print(id)
return sum(id[i] << [24, 16, 8, 0][i] for i in range(4))
print(v1(""127.0.0.1""))
# [127, 0, 0, 1]
# 2130706433
</code></pre>
<pre><code> "“`
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